f(cosx)=cos17x,则f(sinx)=?
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f(cosx)=cos17x,则f(sinx)=?
f(cosx)=cos17x,则f(sinx)=?
f(cosx)=cos17x,则f(sinx)=?
sinx=cos(π/2-x)
所以f(sinx)=f[cos(π/2-x)]=cos[17(π/2-x)]
=cos(17π/2-17x)
=cos(π/2-17x)
=sin17x