∫sinx/(1+sin^4x) ∫sinx/(1+sin^4x) dx
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∫sinx/(1+sin^4x) ∫sinx/(1+sin^4x) dx
∫sinx/(1+sin^4x)
∫sinx/(1+sin^4x) dx
∫sinx/(1+sin^4x) ∫sinx/(1+sin^4x) dx
∫sinx/(1+sin^4x) dx
=∫dcosx/(1+(1-cos^2x)^2)
=∫dcosx/(2-2cos^2x+cos^4x)
=∫du/(2-2u^2+u^4)
=.
查不定积分表 吧