先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1
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![先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1](/uploads/image/z/5371382-38-2.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E8%AE%A1%E7%AE%97x%26%23178%3B-1%2Fx%26%23178%3B%2Bx%C3%B7%28x-%282x-1%29%2Fx%29%2C%E5%85%B6%E4%B8%ADX%3D%E6%A0%B9%E5%8F%B72%2B1)
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先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1
先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1
先化简再计算x²-1/x²+x÷(x-(2x-1)/x),其中X=根号2+1
(x²-1)/(x²+x)÷[x-(2x-1)/x]
=(x²-1)/(x²+x)÷[(x²-2x+1)/x]
=(x²-1)/(x²+x)÷[(x-1)²/x]
=(x²-1)/(x²+x)*x/(x-1)²
=(x-1)(x+1)/[x(x+1)]*x/(x-1)²
=1/(x-1)
=1/(√2+1-1)
=1/√2
=√2/2