x^+y^-4x+8y+20=0,则x+y的值为多少?分解因式:102^-98^
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x^+y^-4x+8y+20=0,则x+y的值为多少?分解因式:102^-98^
x^+y^-4x+8y+20=0,则x+y的值为多少?
分解因式:102^-98^
x^+y^-4x+8y+20=0,则x+y的值为多少?分解因式:102^-98^
x^2+y^2-4x+8y+20=0
x^2-4x+4+y^2+8y+16=0
(x-2)^2+(y+4)^2=0
x-2=0 x=2
y+4=0 y=-4
x+y=2-4=-2
102^2-98^2
=(102+98)(102-98)
=200×4
=800
x^2+y^2-4x+8y+20=0
x^2-4x+4+y^2+8y+16=0
(x-2)^2+(y+4)^2=0
x-2=0 x=2
y+4=0 y=-4
x+y=2-4=-二
102^2-98^2
=(102+98)(102-98)
=200×4
=800
原方程即,
(x-2)^2+(y+4)^2=0,
所以,x=2,y=-4,
x+y=-2.
102^2-98^2=(102+98)(102-98)=200×4=800.
x^+y^-4x+8y+20=0,
(x-2)^2+(y+4)^2=0
(x-2)^2>=0
(y+4)^2>=0
x=2
y=-4
x+y=-2
第一题就是配方。(x-2)^2+(y-4)^2=0 所以X=2 Y=4
第二题=(102+98)*(102-98)
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