几道解一元二次方程的题5x²-根号5*x-6=0(2x-1)²-7=3(x+1)(2x+1)(x-4)=5(x²-3)²-3(3-x²)+2=0
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![几道解一元二次方程的题5x²-根号5*x-6=0(2x-1)²-7=3(x+1)(2x+1)(x-4)=5(x²-3)²-3(3-x²)+2=0](/uploads/image/z/5398144-16-4.jpg?t=%E5%87%A0%E9%81%93%E8%A7%A3%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%9A%84%E9%A2%985x%26%23178%3B-%E6%A0%B9%E5%8F%B75%2Ax-6%3D0%EF%BC%882x-1%EF%BC%89%26%23178%3B-7%3D3%EF%BC%88x%2B1%EF%BC%89%EF%BC%882x%2B1%EF%BC%89%EF%BC%88x-4%EF%BC%89%3D5%EF%BC%88x%26%23178%3B-3%EF%BC%89%26%23178%3B-3%EF%BC%883-x%26%23178%3B%EF%BC%89%2B2%3D0)
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几道解一元二次方程的题5x²-根号5*x-6=0(2x-1)²-7=3(x+1)(2x+1)(x-4)=5(x²-3)²-3(3-x²)+2=0
几道解一元二次方程的题
5x²-根号5*x-6=0
(2x-1)²-7=3(x+1)
(2x+1)(x-4)=5
(x²-3)²-3(3-x²)+2=0
几道解一元二次方程的题5x²-根号5*x-6=0(2x-1)²-7=3(x+1)(2x+1)(x-4)=5(x²-3)²-3(3-x²)+2=0
1.八分之三倍的根号五 或 负 五分之二倍根五
2,x=±八分之根号193加八分之七