一元一次方程的解法2/1[3/x-2/1(2/3x-1)]=12/x 9/1{7/1[5/1(5/x+2+4)+6]+8}=1 4(y+8)=3+5(y-6) 5/x-4-x+4=0 3/x-6/9x+1=1 0.7/1x-3/17-20x=1 x-3/3-2x=1-6/x+2 5/x+4-(x-5)=2/x-2
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![一元一次方程的解法2/1[3/x-2/1(2/3x-1)]=12/x 9/1{7/1[5/1(5/x+2+4)+6]+8}=1 4(y+8)=3+5(y-6) 5/x-4-x+4=0 3/x-6/9x+1=1 0.7/1x-3/17-20x=1 x-3/3-2x=1-6/x+2 5/x+4-(x-5)=2/x-2](/uploads/image/z/539940-12-0.jpg?t=%E4%B8%80%E5%85%83%E4%B8%80%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%9A%84%E8%A7%A3%E6%B3%952%2F1%5B3%2Fx-2%2F1%282%2F3x-1%29%5D%3D12%2Fx+9%2F1%7B7%2F1%5B5%2F1%285%2Fx%2B2%2B4%29%2B6%5D%2B8%7D%3D1+4%28y%2B8%29%3D3%2B5%28y-6%29+5%2Fx-4-x%2B4%3D0+3%2Fx-6%2F9x%2B1%3D1+0.7%2F1x-3%2F17-20x%3D1+x-3%2F3-2x%3D1-6%2Fx%2B2+5%2Fx%2B4-%28x-5%29%3D2%2Fx-2)
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