已知√X(√X+2√Y)=√Y(6√X+5√Y),求(X+√(XY)-Y)/(2X+√(xy)+3Y)的值思路也可以,总之要让人明白,

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 11:43:17
已知√X(√X+2√Y)=√Y(6√X+5√Y),求(X+√(XY)-Y)/(2X+√(xy)+3Y)的值思路也可以,总之要让人明白,
xTn@A@x>ET<Ҧ @Y]Ui<~͌ͪcTBbdgι^;j7,|,8Mz9 VˁP-@AVBmg%ݗ3|x}}&Wt&,}<˿X|egn k7AMdD*7B`h;C8`jtOSkHC[֡<%QX>nFPr@΁:7#DZc3#Q5@mKˑ|޼e oYzyGO;:,֝fPN{I`qtCnDǾ܂l Pߧ67T e~ʷbW)*o(fF[:;pFk@ܒ}wu<$$0cL# 18ON9|0byOC@,z~vUE|6 l <۰DLs

已知√X(√X+2√Y)=√Y(6√X+5√Y),求(X+√(XY)-Y)/(2X+√(xy)+3Y)的值思路也可以,总之要让人明白,
已知√X(√X+2√Y)=√Y(6√X+5√Y),
求(X+√(XY)-Y)/(2X+√(xy)+3Y)的值
思路也可以,总之要让人明白,

已知√X(√X+2√Y)=√Y(6√X+5√Y),求(X+√(XY)-Y)/(2X+√(xy)+3Y)的值思路也可以,总之要让人明白,
√x(√x+2√y)=√y(6√x+5√y),
x+2√xy)=6√xy+5y,
x-4√xy-5y=0,
(√x-5√y)(√x+√y)=0
√x=5√y,(√x=-√y舍去)
(x+√xy-y)/(2x+√xy+3y)
=(25Y+5Y-Y)/(50Y+5Y+3Y)
=1/2
祝你学习天天向上,加油!1

√X(√X+2√Y)=√Y(6√X+5√Y),
x+2√xy=6√xy+5y
x-4√xy-5y=0
(√x-5√y)(√x+√y)=0
√x=5√y
x=25y
(X+√(XY)-Y)/(2X+√(xy)+3Y)
=(25y+5y-y)/(50y+5y+3y)
=29y/58y
=1/2

x+2根号xy=6根号xy+5y
x-4根号xy-5y=0
(根号x+根号y)(根号x-5根号y)=0
根号x+根号y不等于0
根号x=5根号y
(x+√xy-y)/(2x+√xy+3y)
=(25Y+5Y-Y)/(50Y+5Y+3Y)
=1/2

√X(√X+2√Y)=√Y(6√X+5√Y),
化为 x-5y=4√xy
∴(x-5y)²=16xy
∴x²-26xy+25y²=0
∴(x-y)(x-25y)=0
∴x=y 或x=25y
当x=y时
(X+√(XY)-Y)/(2X+√(xy)+3Y)
=(y+5y-y)/(2y+y+3y)
=5...

全部展开

√X(√X+2√Y)=√Y(6√X+5√Y),
化为 x-5y=4√xy
∴(x-5y)²=16xy
∴x²-26xy+25y²=0
∴(x-y)(x-25y)=0
∴x=y 或x=25y
当x=y时
(X+√(XY)-Y)/(2X+√(xy)+3Y)
=(y+5y-y)/(2y+y+3y)
=5y/6y
=5/6
当x=25y时
(X+√(XY)-Y)/(2X+√(xy)+3Y)
=(25y+5y-y)/(50y+5y+3y)
=29y/58y
=1/2

收起