如图,△ABC是等腰直角三角形,∠ABC=90°,AB=10,D为△ABC外一点,连接AD、BD,过D作DH⊥AB,垂足为H 若BD=AB,且tan∠HDB=3/4.求DE的长.急.谢谢
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![如图,△ABC是等腰直角三角形,∠ABC=90°,AB=10,D为△ABC外一点,连接AD、BD,过D作DH⊥AB,垂足为H 若BD=AB,且tan∠HDB=3/4.求DE的长.急.谢谢](/uploads/image/z/5405567-23-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E2%96%B3ABC%E6%98%AF%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%2C%E2%88%A0ABC%EF%BC%9D90%C2%B0%2CAB%3D10%2CD%E4%B8%BA%E2%96%B3ABC%E5%A4%96%E4%B8%80%E7%82%B9%2C%E8%BF%9E%E6%8E%A5AD%E3%80%81BD%2C%E8%BF%87D%E4%BD%9CDH%E2%8A%A5AB%2C%E5%9E%82%E8%B6%B3%E4%B8%BAH+%E8%8B%A5BD%3DAB%2C%E4%B8%94tan%E2%88%A0HDB%3D3%2F4.%E6%B1%82DE%E7%9A%84%E9%95%BF.%E6%80%A5.%E8%B0%A2%E8%B0%A2)
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