已知2a+3b-c=0,a+3b+c=0,求a^2+2b^2+c^2/a^2-2b^2+2c^2的值
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已知2a+3b-c=0,a+3b+c=0,求a^2+2b^2+c^2/a^2-2b^2+2c^2的值
已知2a+3b-c=0,a+3b+c=0,求a^2+2b^2+c^2/a^2-2b^2+2c^2的值
已知2a+3b-c=0,a+3b+c=0,求a^2+2b^2+c^2/a^2-2b^2+2c^2的值
2a+3b-c=0①
a+3b+c=0②
①②相加得到:a+2b=0,所以a=-2b
又②知道a+2b+b+c=0得到b+c=0,所以b=-c
a^2+2b^2+c^2/a^2-2b^2+2c^2
=(a^2+2b^2+b^2)/(a^2-2b^2+2b^2)
=(a^2+3b^2)/a^2
=1+3b^2/a^2
=1+3/4
=7/4