作业帮化简6log2/3-4log10/9+2 log 25/6=?
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化简6log2/3-4log10/9+2 log 25/6=?
化简6log2/3-4log10/9+2 log 25/6=?
化简6log2/3-4log10/9+2 log 25/6=?
6log2/3-4log10/9+2 log 25/6
=2×（3log2/3-2log10/9+log 25/6）
=2×[log(2/3)^3/(10/9)^2×25/6]
=2×[log8/27×81/100×25/6]
=2×log1
=0
化简6log2/3-4log10/9+2 log 25/6=?
log10是什么?log 75 - log 3 + log 4＝log25＋log3－log3＋2log2＝2log5＋2log2＝2log10=2 ,这样看log10=1,可我只知道lg10=1,log10或者logx x是纯数字,没有底数...郁闷,大虾教教
计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9
log2^(4^7*2^5)+log2^6-log2^3
log10(x^3) + log10(y^2) = 11 log10(x^2) + log10(y^3) = 3 求解方程组.
化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32
计算：log2(log2 32-log2 3/4+log2 6)
log10 4-log10 5+2log10 √125麻烦写出过程
(log3^4+log5^2)(log2^9+log2^根号3)
(log2 9)/(log2 8) = 2/3(log2 3)
求值:log2(32)+log2(6)-log2(3/4)
解方程log2【9^2-4】=log2【3^x-2】+3答案是log3【6】
化简：(log2(x/4))*(log2(x/2))
log2 6-log2 3
log2^6-log2^3
log2(4)/log2(3)
2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X