如图△ABC中,∠BAC=90°,AB=AC,M是AC的中点,AE⊥BM于E并延长交BC于D,求证∠AMB=∠CMD
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![如图△ABC中,∠BAC=90°,AB=AC,M是AC的中点,AE⊥BM于E并延长交BC于D,求证∠AMB=∠CMD](/uploads/image/z/5447132-44-2.jpg?t=%E5%A6%82%E5%9B%BE%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0%2CAB%3DAC%2CM%E6%98%AFAC%E7%9A%84%E4%B8%AD%E7%82%B9%2CAE%E2%8A%A5BM%E4%BA%8EE%E5%B9%B6%E5%BB%B6%E9%95%BF%E4%BA%A4BC%E4%BA%8ED%2C%E6%B1%82%E8%AF%81%E2%88%A0AMB%3D%E2%88%A0CMD)
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