作业帮把下列分式化为最简分式[a²-(b²-c²)]/[(a+b)²-c²]
来源：学生作业帮助网 编辑：作业帮 时间：2024/10/04 05:38:05
![把下列分式化为最简分式[a²-(b²-c²)]/[(a+b)²-c²]](/uploads/image/z/5462825-41-5.jpg?t=%E6%8A%8A%E4%B8%8B%E5%88%97%E5%88%86%E5%BC%8F%E5%8C%96%E4%B8%BA%E6%9C%80%E7%AE%80%E5%88%86%E5%BC%8F%5Ba%26%23178%3B-%28b%26%23178%3B-c%26%23178%3B%29%5D%2F%5B%28a%2Bb%29%26%23178%3B-c%26%23178%3B%5D)
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把下列分式化为最简分式[a²-(b²-c²)]/[(a+b)²-c²]
把下列分式化为最简分式
[a²-(b²-c²)]/[(a+b)²-c²]
把下列分式化为最简分式[a²-(b²-c²)]/[(a+b)²-c²]
那个,你确定题没错么~ 如果是【a平方-(b-c)平方】/【(a+b)平方-c平方】的话,
原式=( a+b-c) *[ a-(b-c)] / (a+b+c) (a+b-c)
=( a+b-c) *(a-b+c) / (a+b+c) (a+b-c)
=(a-b+c) / (a+b+c)