已知:如图,点C为线段AB上一点,△ACM、△CBN是等边三角形,AN交CM于点E,BM交CN于点F.求证AE=BF(若不等也请说明理由)谢谢,
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![已知:如图,点C为线段AB上一点,△ACM、△CBN是等边三角形,AN交CM于点E,BM交CN于点F.求证AE=BF(若不等也请说明理由)谢谢,](/uploads/image/z/5464911-39-1.jpg?t=%E5%B7%B2%E7%9F%A5%3A%E5%A6%82%E5%9B%BE%2C%E7%82%B9C%E4%B8%BA%E7%BA%BF%E6%AE%B5AB%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E2%96%B3ACM%E3%80%81%E2%96%B3CBN%E6%98%AF%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2%2CAN%E4%BA%A4CM%E4%BA%8E%E7%82%B9E%2CBM%E4%BA%A4CN%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81AE%3DBF%28%E8%8B%A5%E4%B8%8D%E7%AD%89%E4%B9%9F%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1%EF%BC%89%E8%B0%A2%E8%B0%A2%2C)
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