设全集U=R,A=(-∞,-2) ∪[5,+∞),B={x∣a+1≤x≤2a-1},且B⊆CuA,求实数a的取
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![设全集U=R,A=(-∞,-2) ∪[5,+∞),B={x∣a+1≤x≤2a-1},且B⊆CuA,求实数a的取](/uploads/image/z/5465408-32-8.jpg?t=%E8%AE%BE%E5%85%A8%E9%9B%86U%3DR%2CA%3D%28-%E2%88%9E%2C-2%29+%E2%88%AA%5B5%2C%2B%E2%88%9E%29%2CB%3D%7Bx%E2%88%A3a%2B1%E2%89%A4x%E2%89%A42a-1%7D%2C%E4%B8%94B%26%238838%3BCuA%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96)
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设全集U=R,A=(-∞,-2) ∪[5,+∞),B={x∣a+1≤x≤2a-1},且B⊆CuA,求实数a的取
设全集U=R,A=(-∞,-2) ∪[5,+∞),B={x∣a+1≤x≤2a-1},且B⊆CuA,求实数a的取
设全集U=R,A=(-∞,-2) ∪[5,+∞),B={x∣a+1≤x≤2a-1},且B⊆CuA,求实数a的取
因为A=(-∞,-2) ∪[5,+∞),所以CuA{-2,5}
又因为B⊆CuA,所以a+1≥-2,2a-1≤5
解出a{-3≤a≤3}