1*3*5*7-1=104=8*13,3*5*7*9-1=944=8*118……试证:四个连续奇数的乘积减去1的差,必定能被8整除.1*3*5*7-1=104=8*13,3*5*7*9-1=944=8*118……试证:四个连续奇数的乘积减去1的差,必定能被8整除.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 23:06:28
![1*3*5*7-1=104=8*13,3*5*7*9-1=944=8*118……试证:四个连续奇数的乘积减去1的差,必定能被8整除.1*3*5*7-1=104=8*13,3*5*7*9-1=944=8*118……试证:四个连续奇数的乘积减去1的差,必定能被8整除.](/uploads/image/z/5468853-21-3.jpg?t=1%2A3%2A5%2A7-1%3D104%3D8%2A13%2C3%2A5%2A7%2A9-1%3D944%3D8%2A118%E2%80%A6%E2%80%A6%E8%AF%95%E8%AF%81%3A%E5%9B%9B%E4%B8%AA%E8%BF%9E%E7%BB%AD%E5%A5%87%E6%95%B0%E7%9A%84%E4%B9%98%E7%A7%AF%E5%87%8F%E5%8E%BB1%E7%9A%84%E5%B7%AE%2C%E5%BF%85%E5%AE%9A%E8%83%BD%E8%A2%AB8%E6%95%B4%E9%99%A4.1%2A3%2A5%2A7-1%3D104%3D8%2A13%2C3%2A5%2A7%2A9-1%3D944%3D8%2A118%E2%80%A6%E2%80%A6%E8%AF%95%E8%AF%81%3A%E5%9B%9B%E4%B8%AA%E8%BF%9E%E7%BB%AD%E5%A5%87%E6%95%B0%E7%9A%84%E4%B9%98%E7%A7%AF%E5%87%8F%E5%8E%BB1%E7%9A%84%E5%B7%AE%2C%E5%BF%85%E5%AE%9A%E8%83%BD%E8%A2%AB8%E6%95%B4%E9%99%A4.)
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