(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算:(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 11:45:48
![(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算:(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值](/uploads/image/z/5475766-22-6.jpg?t=%EF%BC%88%E2%88%9A2-1%EF%BC%89%EF%BC%88%E2%88%9A2%2B1%EF%BC%89%3D1%2C%EF%BC%88%E2%88%9A3-%E2%88%9A2%EF%BC%89%EF%BC%88%E2%88%9A3%2B%E2%88%9A2%EF%BC%89...%E5%88%A9%E7%94%A8%E4%B8%8A%E8%BF%B0%E8%A7%84%E5%BE%8B%E8%BF%90%E7%AE%97%EF%BC%88%E2%88%9A2-1%EF%BC%89%EF%BC%88%E2%88%9A2%2B1%EF%BC%89%3D1%2C%EF%BC%88%E2%88%9A3-%E2%88%9A2%EF%BC%89%EF%BC%88%E2%88%9A3%2B%E2%88%9A2%EF%BC%89...%E5%88%A9%E7%94%A8%E4%B8%8A%E8%BF%B0%E8%A7%84%E5%BE%8B%E8%BF%90%E7%AE%97%EF%BC%9A%EF%BC%881%2F%EF%BC%881%2B%E2%88%9A2%EF%BC%89%2B1%2F%EF%BC%88%E2%88%9A2%2B%E2%88%9A3%EF%BC%89%2B...%2B1%2F%28%E2%88%9A2002%2B2003%29%281%2B%E2%88%9A2003%EF%BC%89%E7%9A%84%E5%80%BC)
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(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算:(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值
(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算
(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...
利用上述规律运算:(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值
(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...利用上述规律运算:(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值
(1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)
=【√2-1+√3-√2+……+√2003-√2002】(1+√2003)
=(√2003 -1)×(1+√2003)
=2003-1
=2002
呃
答案为2002
(√2-1)(√2+1)=1,(√3-√2)(√3+√2)...
利用上述规律运算: (1/(1+√2)+1/(√2+√3)+...+1/(√2002+2003)(1+√2003)的值
(√3+√2)*(√3-√2)= √1/7+√28-√700=
2√2(√2+1/√2)-(√27-√12/√3)
√1/5=(),计算:√2/3-√3/2,√18-√8+√1/8,√25/2+√99-√18
|√6|-√2+√(√2-1)² -√(√6-3)²
观察下列计算:1/√2+√1=√2-√1;1/√3+√2=√3-√2;1/√4+√3=√4-√3;1/√5+√4=√5-√4;...从计算中找出规律,并利用这一规律计算:(1/√2+√1+1/√3+√2+1/√4+√3+...+1/√2012+√2011)×(√2012+1)
√24+√32/2√2-√27=?(3√18+1/5√50-4√1/2)/√32=?√24+√32/2√2-√27=?打错了应该是(√24+√32)/2√2-√27=?把√1+√112,√2+√11,√3+√10,√4+√9,√5+√8,√6+√7 从大到小排列起来,找出它的的
实数的运算 [急]√96-√24=√3(√3-1)=√20+√5/√5-√1/3*√2=√54=√2-5√1/2+√32=(√5-√2)平方=(√6-√2)(√2+√6)=|1-√2|+|√2-√3|+|√3-2|=√12*√6/√2=..
(√45+√18)-(√8-√125)=?1/2(√2+√3)-3/4(√2+√27)=?
1 √32-3√1/2+√22 √12+√27/√3-√1/3×√123 √50+√30/√8-44 √24+√216/√6+55 (√6-2√15)×√3-6√1/26 √2/3-4√216+43√1/67 √8+√30-√28 √1/7+√63-√1129 √40-5√1/10+√1010 √2+√8/√2
(√3+1)²-2(√3+√2)(√3-√2)
计算:①(√5-1)^2+(4/√5-1)②(√2+√3+√6)×(√2-√3+√6)③√27-(√1/3)=________④(√8又1/3)-(√3/8)-√54+(√1/3)=________⑤√3+√12-3√18+7√2⑥√48-1/3+√0.75⑦√75-(1/√3-√2)+
(√5-√3)²+√60-(√2+1)(√2-1)
①(√3+√2)+(√3-√2)/(√3+√2)-(√3-√2)②x^2-x-3=0③√18-2/√2-√8/2+(√5-1)^0
(√6-√2分之1)-(√54+√8分之1)=?(√x+√y)(3√x-√y)=?
(√5+2√3)(-√5+2√3)=?(2√3-1)²=?√32÷(√8+√18)=?
1、(√3-√2+√6)*(√3+√2-√6)2、已知:x=(√3-√2)/2y=(√3+√2)/2求(1/x)-(1/y)的值.
计算3√2×√2/3-√(2-√5)+1/√5+2
1、 4√12 - 9√1/3 + 1/2√752、 (√5+√3-√2)(√5-√3+√2)