{ x+y+z=2 x-z=-2 y+z=1的解(求过程)
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{ x+y+z=2 x-z=-2 y+z=1的解(求过程)
{ x+y+z=2 x-z=-2 y+z=1的解(求过程)
{ x+y+z=2 x-z=-2 y+z=1的解(求过程)
x+y+z=2,y+z=1 => x=1
x=1,x-z=-2 => z=3
z=3,y+z=1 => y=-2
x+y+z=z-x 2x+y=0
y+z-(z-x)=-1 x+y=-1
x=1 y=-2 z=3
因为:X-Z=-2,则有:X=Z-2
因为:Y+Z=1,则有:Y=1-Z
则X+Y+Z=(Z-2)+(1-Z)+Z=2
有:Z-1=2,Z=3
X=3-1=2
Y=1-3=-2
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