(1)2x+3/1=3 (2)2/1(3x+1)-4=x-1 (3)4-3x=-8 (4)3x-8x=2/1 (5)-x=-2/1(x+4) (6)2/3x+3/1=-2/1(x+2)
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![(1)2x+3/1=3 (2)2/1(3x+1)-4=x-1 (3)4-3x=-8 (4)3x-8x=2/1 (5)-x=-2/1(x+4) (6)2/3x+3/1=-2/1(x+2)](/uploads/image/z/5494892-68-2.jpg?t=%281%292x%2B3%2F1%3D3+%282%292%2F1%283x%2B1%29-4%3Dx-1+%283%294-3x%3D-8+%284%293x-8x%3D2%2F1+%285%29-x%3D-2%2F1%28x%2B4%29+%286%292%2F3x%2B3%2F1%3D-2%2F1%28x%2B2%29)
(1)2x+3/1=3 (2)2/1(3x+1)-4=x-1 (3)4-3x=-8 (4)3x-8x=2/1 (5)-x=-2/1(x+4) (6)2/3x+3/1=-2/1(x+2)
(1)2x+3/1=3 (2)2/1(3x+1)-4=x-1
(3)4-3x=-8 (4)3x-8x=2/1
(5)-x=-2/1(x+4) (6)2/3x+3/1=-2/1(x+2)
(1)2x+3/1=3 (2)2/1(3x+1)-4=x-1 (3)4-3x=-8 (4)3x-8x=2/1 (5)-x=-2/1(x+4) (6)2/3x+3/1=-2/1(x+2)
(1)解,由原式移项2x=3-3
得2x=0
化系数为1两边同除2
x=0
(2)去括号,所以要用分配律
6x+2-4=x-1
6x-2=x-1
移项5x=1
x=1/5
(3)移项,两边同减4得-3x=-12
同时除-3
由负负得正得x=4
(4)-5x=2
两边同除5
x=-2/5
(5)右边用分配律去括号得-x=-2x-8,移项的-x+2x=-8,x-=-8
(6)先把右边用分配律去括号2/3x+3=-2x-4,再移项得8/3x=-7,两边同除8/3得x=x=-21/8
(1)x=0,
(1)移项得 2x=3-3
则2x=0
两边同除2
得x=0
(2)去括号,得 6x+2-4=x-1
6x-2=x-1
...
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(1)移项得 2x=3-3
则2x=0
两边同除2
得x=0
(2)去括号,得 6x+2-4=x-1
6x-2=x-1
移项5x=1
x=1/5
(3)移项,两边同减4得 -3x=-12
两边同除-3
得x=4
(4) -5x=2
两边同除5,得
x=-2/5
(5)去括号得 -x=-2x-8 移项得 -x+2x=-8 得 x-=-8
(6)去括号2/3x+3=-2x-4,移项得8/3x=-7,两边同除8/3得x=x=-21/8
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