x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
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x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)
后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
哥!你那个是x方y方吧!
有这么个公式 x方-y方=(x+y)(x-y)
所以得到了(x+y)(x-y)-(x+y)
这时候提取公因式(x+y)就得到了(x+y)(x-y-1)
提出(x+y),得(x+y)(x-y)-(x+y) =(x+y)(x-y-1)
(x+y)(x-y)-(x+y)这个式子提取(x+y)后,减号左边得到的是(x-y)。右边是1。结果就是(x+y)(x-y-1)
把 (x+y)看做整体提取公因式
(x+y)(x-y)-(x+y)
=(x+y)(x-y)-(x+y)×1
=(x+y)(x-y-1)
二元二次方程组:(X2+X2/2=Y2 X/2+X+Y=6)解法
x2+x+y2/x+y
x2+y2=208(x-y)
(x-y)(x2+xy+y2)
(x+y)(x2-xy+y2)
X2y2-x2-y2+1 =x2(y2-1)-(y2-1) =(y2-1)(x2-1) =(y+1)(y-1)(x+1)(x-1) 中的=x2(y2-1)-(y2-1) =(y2-1)(x2-1是怎么算出来的?
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y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2)
我做对了吗.x2(x-y)+y2(y-x)= x2(x-y)-y2(x-y)=x2-y2=(x+y)(x-y)
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