x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 10:11:43
x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
xRN@hCu0n]iR!!11y\)͊_HUl\4ӹs=4,Ud[mii^ez֎tqJ2\'(`N 0!C?nAli$kvN\ŪC?p;)`콎$#Dh"(q'@KGqCNH 4Q{ KO?{d5q.RrXϏbq&_w<ݕK.!O7#Ә-&)>v%{춁 kJrRظcU^HLęGMh|d

x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)
后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的

x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)后半部的解法(x+y)(x-y)-(x+y) =(x+y)(x-y-1)怎么得的
哥!你那个是x方y方吧!
有这么个公式 x方-y方=(x+y)(x-y)
所以得到了(x+y)(x-y)-(x+y)
这时候提取公因式(x+y)就得到了(x+y)(x-y-1)

提出(x+y),得(x+y)(x-y)-(x+y) =(x+y)(x-y-1)

(x+y)(x-y)-(x+y)这个式子提取(x+y)后,减号左边得到的是(x-y)。右边是1。结果就是(x+y)(x-y-1)

把 (x+y)看做整体提取公因式
(x+y)(x-y)-(x+y)
=(x+y)(x-y)-(x+y)×1
=(x+y)(x-y-1)