设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8,求a,b设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A设f(x)=[2(log2(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有

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设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8,求a,b设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A设f(x)=[2(log2(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有
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设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8,求a,b设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A设f(x)=[2(log2(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有
设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8,求a,b
设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A
设f(x)=[2(log2(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A 刚才写错了。

设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8,求a,b设f(x)=[2(logx(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有最小值-8.(1)求a,b(2)求满足f(x)>0的x的集合A设f(x)=[2(log2(x))^2]+2alog2(1/x)+b,已知x=1/2时,f(x)有
f(x)=[2(log2(x))^2]+2alog2(1/x)+b
=[2(log2(x))^2]-2alog2(x)+b
令log2(x)=t
则可换为:
f(t)=2t^2-2at+b
而抛物线在对称轴处取得最值,而次抛物线开口向上,则取得最小值
即:f(t)=2(t-a/2)^2+b-a^2/2
而此时t=a/2时,取得最小值
由题意,当x=1/2时,f(x)有最小值-8
则:x=1/2,则t=-1
a/2=-1
b-a^2/2=-8
则,a=-2,b=-6
则:
f(t)=2t^2+4t-6=2(t+3)(t-1)
f(x)>0
则t>1,或者t<-3
则可知
log2(x)>1,或者log2(x)<-3
则,02

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