作业帮已知函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a 2)若x属于[-π/2,π/2]时,最大值最小值之和为√3,求a的值.
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![已知函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a 2)若x属于[-π/2,π/2]时,最大值最小值之和为√3,求a的值.](/uploads/image/z/5503571-35-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dsin%28x%2B%CF%80%2F6%29%2Bsin%28x-%CF%80%2F6%29%2Bcosx%2Ba+2%29%E8%8B%A5x%E5%B1%9E%E4%BA%8E%5B-%CF%80%2F2%2C%CF%80%2F2%5D%E6%97%B6%2C%E6%9C%80%E5%A4%A7%E5%80%BC%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B9%8B%E5%92%8C%E4%B8%BA%E2%88%9A3%2C%E6%B1%82a%E7%9A%84%E5%80%BC.)
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已知函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a 2)若x属于[-π/2,π/2]时,最大值最小值之和为√3,求a的值.
已知函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a 2)若x属于[-π/2,π/2]时,最大值最小值之和为√3,求a的值.
已知函数f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a 2)若x属于[-π/2,π/2]时,最大值最小值之和为√3,求a的值.
我觉得题目那个a后面的2是不是没有啊,思路就是这样.
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