作业帮已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2＜a＜π,0＜b＜π/2,求cos（a+b）的值
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已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2＜a＜π,0＜b＜π/2,求cos（a+b）的值
已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2＜a＜π,0＜b＜π/2,求cos（a+b）的值
已知cos[a-(b/2)]=-1/9,sin(a/2-b)=2/3,且π/2＜a＜π,0＜b＜π/2,求cos（a+b）的值
http://zhidao.baidu.com/question/168604222.html
算法一样,只是数值有点差别