作业帮f(x)=1/3x³+[（a-2）/2 ] x²-2ax-3,g（a）=1/6a³+5a-7f(x)在区间[-2,0]不单调 且x属于[-2,0]时,不等式f(x)
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/08 17:25:01
![f(x)=1/3x³+[（a-2）/2 ] x²-2ax-3,g（a）=1/6a³+5a-7f(x)在区间[-2,0]不单调 且x属于[-2,0]时,不等式f(x)](/uploads/image/z/5506271-71-1.jpg?t=f%28x%29%3D1%2F3x%26%23179%3B%2B%5B%EF%BC%88a-2%EF%BC%89%2F2+%5D+x%26%23178%3B-2ax-3%2Cg%EF%BC%88a%EF%BC%89%3D1%2F6a%26%23179%3B%2B5a-7f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-2%2C0%5D%E4%B8%8D%E5%8D%95%E8%B0%83+%E4%B8%94x%E5%B1%9E%E4%BA%8E%5B-2%2C0%5D%E6%97%B6%2C%E4%B8%8D%E7%AD%89%E5%BC%8Ff%28x%29)
x͐JA_eA]an_$DC-l QbR =iA>&+dj67Zn[UjUb}ǻ]Ph Hڸ6 t\>سr'z>Vϯ}Ջ4Ǒ.3;8 Y쟽0i91QvXr[4nHʹPp*CN5(wɲ3ߙ 0) 8lEsLK{wojC 䪟L~"@Z9'
f(x)=1/3x³+[（a-2）/2 ] x²-2ax-3,g（a）=1/6a³+5a-7f(x)在区间[-2,0]不单调 且x属于[-2,0]时,不等式f(x)
f(x)=1/3x³+[（a-2）/2 ] x²-2ax-3,g（a）=1/6a³+5a-7
f(x)在区间[-2,0]不单调 且x属于[-2,0]时,不等式f(x)
f(x)=1/3x³+[（a-2）/2 ] x²-2ax-3,g（a）=1/6a³+5a-7f(x)在区间[-2,0]不单调 且x属于[-2,0]时,不等式f(x)
f(x)=(1/3)x^3+((a-2)/2)x^2-2ax-3
f'(x)=x^2+(a-2)x-2a=(x+a)(x-2)
0>-a>-2时,
-a0递增
x=-a,f'(x)=0 [-2,0] f(-a)是最大值
f(-a)=(1/3)(-a)^3+((a-2)/2)*(-a)^2+2a^2-3=(1/6)a^3+a^2-3
f(-a)