4x^2-(2x^2+x-1)+(2-x^2+3x),其中x=2

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4x^2-(2x^2+x-1)+(2-x^2+3x),其中x=2
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4x^2-(2x^2+x-1)+(2-x^2+3x),其中x=2
4x^2-(2x^2+x-1)+(2-x^2+3x),其中x=2

4x^2-(2x^2+x-1)+(2-x^2+3x),其中x=2
4x^2-(2x^2+x-1)+(2-x^2+3x),
=4x²-2x²-x+1+2-x²+3x
=x²+2x+3
当x=2时
原式=4+4+3=11


4x²-(2x²+x-1)+(2-x²+3x)
=(4x²-2x²-x²)+(-x+3x)+(1+2)
=x²+2x+3
将x=2代入
原式
=4+2×2+3
=8+3
=11

4x²-(2x²+x-1)+(2-x²+3x)
=4x²-2x²-x+1+2-x²+2x
=x²+x+3
=2²+2+3
=9

4x^2-(2x^2+x-1)+(2-x^2+3x)
=4*(2^2)-(2*2^2+2-1)+(2-2^2-3*2)
=4*4-(8+2-1)+(2-4-6)
=16-9-8
=-1

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