已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
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已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
已知4sin^2x-cos^2x+3cosx=0求(cos2x-cos^2x)/(1-cot^2x)
4[1-(cosx)^2]-(cosx)^2+3cosx
=4-5(cosx)^2+3cosx=0
5(cosx)^2-3cosx-4=0
(cosx)^2-(3/5)cos+(3/10)^2=4/5+(3/10)^2
所以cosx=3/10±√89/10
因为-1《cosx《1 所以cosx=3/10-√89/10
[cos2x-(cosx)^2]/[1-(cotx)^2]
=[2(cosx)^2-1-(cosx)^2]/{[(sinx)^2-(cosx)^2]/(sinx)^2}
=[(cosx)^2-1]*[1-(cosx)^2]/[1-2(cosx)^2]
=
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