闭合电路的欧姆定律 已知四个电阻的阻值为:R1=1Ω、R2=2Ω、R3=3Ω、R4=4Ω,电源电动势E=4V,内阻r=0.2Ω:求1.S闭合,S'断开时,通过R1和R2的电流之比I1/I2;2.S和S'都闭合时的总电流I'
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闭合电路的欧姆定律 已知四个电阻的阻值为:R1=1Ω、R2=2Ω、R3=3Ω、R4=4Ω,电源电动势E=4V,内阻r=0.2Ω:求1.S闭合,S'断开时,通过R1和R2的电流之比I1/I2;2.S和S'都闭合时的总电流I'
闭合电路的欧姆定律
已知四个电阻的阻值为:R1=1Ω、R2=2Ω、R3=3Ω、R4=4Ω,电源电动势E=4V,内阻r=0.2Ω:求
1.S闭合,S'断开时,通过R1和R2的电流之比I1/I2;
2.S和S'都闭合时的总电流I'
闭合电路的欧姆定律 已知四个电阻的阻值为:R1=1Ω、R2=2Ω、R3=3Ω、R4=4Ω,电源电动势E=4V,内阻r=0.2Ω:求1.S闭合,S'断开时,通过R1和R2的电流之比I1/I2;2.S和S'都闭合时的总电流I'
闭合时:
I1=U/(R1+R3)=U/4
I2=U/(R2+R4)=U/6
I1/I2=6/4=3:2
闭合S1后~R1.R2并联 R3.R4并联 之后两者串联!
R总=1//2 +3//4+0.2
R总=2/3+12/7+0.2
I=E/R总=4/(2/3+7/12+0.2)=2.76A
1为上下两路的并联,电阻为4和6,所以电流比是3:2
2为12并联串上34并联,总电阻为2/3+12/7+0.2=2521/105
总电流I=420/1521 约等于2.76A
NO.1 S闭合 S'断开 流过R1和R2电流比为 (R2+R4):(R1+R3)= 3:2
NO.2 全部闭合 R1 R2并联 并 和R3 R4组成的串联 故总电流为I= 4 / (0.2+2/3+12/7) =1.55A
前面两位今天几号。