高次方程求解X^4+8X-48=0

来源：学生作业帮助网编辑：作业帮时间：2024/11/16 00:02:57

x��)�{�zƳ5�M��|E��M/�/��3Ѷ��5��5�I*�Ǣ,��L��Ά��@%Ov�3+m �ML��̌�3!�F � P]Tc[#=cK��VA�H��F�� 1��,0h��Q��0�6�225�h�i�k��i�c�e4!��H2��

高次方程求解X^4+8X-48=0
高次方程求解
X^4+8X-48=0

高次方程求解X^4+8X-48=0
X^4+8X-48=0
解为
x1=0.1443 + 2.6361i
x2 = 0.1443 - 2.6361i
x3 =2.4839
x4= -2.7725

全部展开

x1=1/2*2^(1/2)*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+1/2*i*((2*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)*(4+4*257^(1/2))^(2/3)-32*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(4+4*257^(1/2))^(1/3))/(4+4*257^(1/2))^(1/3)/(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2))^(1/2)
x2=1/2*2^(1/2)*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)-1/2*i*((2*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)*(4+4*257^(1/2))^(2/3)-32*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(4+4*257^(1/2))^(1/3))/(4+4*257^(1/2))^(1/3)/(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2))^(1/2)
x3=-1/2*2^(1/2)*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+1/2*((-2*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)*(4+4*257^(1/2))^(2/3)+32*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(4+4*257^(1/2))^(1/3))/(4+4*257^(1/2))^(1/3)/(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2))^(1/2)
x4=-1/2*2^(1/2)*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)-1/2*((-2*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)*(4+4*257^(1/2))^(2/3)+32*(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2)+8*2^(1/2)*(4+4*257^(1/2))^(1/3))/(4+4*257^(1/2))^(1/3)/(((4+4*257^(1/2))^(2/3)-16)/(4+4*257^(1/2))^(1/3))^(1/2))^(1/2)

收起

高次方程求解X^4+8X-48=0 高次方程求解高次方程x^4+24x^3+70x^2-1176x-7056=0求解. 求解高次方程 3X^4-32X^3+256X^2-784=0在线等急求分解高次方程求解急x^4-18x^3+kx^2+200x-1984=0已知两根积为-32求常数k 求解6次方程x^6-1=0 求解特殊的高次方程X^3-3x^2+x+2=0如果方程x^3-4x^2+ax=0有且只有一个实数根.则a的取值范围是什么.就这辆题. 6次方程求解x^6-8x^5+16x^4+2048x-4096=0要求保留根号,求出来的加100分求解一个一元三次方程x的3次-x的2次-2x=0求x 3次方程求解 x3+3x2-8x-24=0 求解一元三次方程 18X3次-45X+8=0 求其正根求解一道3次方程：x^3-27x^2+24x+1760=0 方程3x^2+8x-4=0求解, 求解高次方程求解1元3次方程!-2X^3+X^2+1=0 3x^4--2x^3---2x^2---2x+3=0,这个高次方程怎么解? 几个高次方程 x^3-9x+8=0 (x+2)(x+3)(x+4)(x+5)=360 (x^-x)^2+4(3x^2-3x-7)=0 急求用matlab 解一个一元高次方程sqrt((1.35-0.0250/(x^4)）*(x^5.29)/1.7446)-sqrt((3.1941/(x^4)-4.92)*(x^5.29)/1.0263)=15.37求解x的值.第一个括号要去掉谁帮我解一个高次方程啊32X^4-48X^3+18X^2+X+1=0我急用啊