以能让我看懂为准第一道若x1满足,2x+2^x=5.x2满足2x+2log2(x-1)=5,则x1+x2=第二道若f(x)=-f(x),f(2a-x)=f(x) 求证f(x)为周期函数,求周期第二道,写错了应该是f(x)=-f(-x),2log2(x-1)
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![以能让我看懂为准第一道若x1满足,2x+2^x=5.x2满足2x+2log2(x-1)=5,则x1+x2=第二道若f(x)=-f(x),f(2a-x)=f(x) 求证f(x)为周期函数,求周期第二道,写错了应该是f(x)=-f(-x),2log2(x-1)](/uploads/image/z/5543360-8-0.jpg?t=%E4%BB%A5%E8%83%BD%E8%AE%A9%E6%88%91%E7%9C%8B%E6%87%82%E4%B8%BA%E5%87%86%E7%AC%AC%E4%B8%80%E9%81%93%E8%8B%A5x1%E6%BB%A1%E8%B6%B3%2C2x%2B2%5Ex%3D5.x2%E6%BB%A1%E8%B6%B32x%2B2log2%EF%BC%88x-1%EF%BC%89%3D5%2C%E5%88%99x1%2Bx2%3D%E7%AC%AC%E4%BA%8C%E9%81%93%E8%8B%A5f%EF%BC%88x%EF%BC%89%3D-f%EF%BC%88x%EF%BC%89%2Cf%EF%BC%882a-x%EF%BC%89%3Df%EF%BC%88x%EF%BC%89+%E6%B1%82%E8%AF%81f%EF%BC%88x%EF%BC%89%E4%B8%BA%E5%91%A8%E6%9C%9F%E5%87%BD%E6%95%B0%2C%E6%B1%82%E5%91%A8%E6%9C%9F%E7%AC%AC%E4%BA%8C%E9%81%93%EF%BC%8C%E5%86%99%E9%94%99%E4%BA%86%E5%BA%94%E8%AF%A5%E6%98%AFf%EF%BC%88x%EF%BC%89%3D-f%EF%BC%88-x%EF%BC%89%EF%BC%8C2log2%EF%BC%88x-1%EF%BC%89)
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