若n²+3n=1,求n(n+1)(n+2)(n+3)+1的值
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若n²+3n=1,求n(n+1)(n+2)(n+3)+1的值
若n²+3n=1,求n(n+1)(n+2)(n+3)+1的值
若n²+3n=1,求n(n+1)(n+2)(n+3)+1的值
n(n+1)(n+2)(n+3)+1
=(n+1)(n+2)n(n+3)+1
=(n²+3n+3)(n²+3n)+1
=4x1+1
=5
解由n(n+1)(n+2)(n+3)+1
=n(n+3)(n+1)(n+2)+1
=(n²+3n)(n²+3n+2)+1
=1*(1+2)+1
=3+1
=4
n(n+3)=1
n(n+1)(n+2)(n+3)=n(n+3)(n+2)(n+1)=(n+2)(n+1)=n^2+3n+2=3
所以结果为4.代入法比较简单
+3n=1
n=1除以3
n=1/3将n=1/3
代入n(n+1) (n+2) (n+3)+1