把函数f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.(1)求φ的值(2)求函数h(x)=f(x-π/12)-g(x)的单调增区间
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/09 04:36:58
![把函数f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.(1)求φ的值(2)求函数h(x)=f(x-π/12)-g(x)的单调增区间](/uploads/image/z/5551269-69-9.jpg?t=%E6%8A%8A%E5%87%BD%E6%95%B0f%28x%29%3D2sin%282x%2B%CF%86%29%280%EF%BC%9C%CF%86%EF%BC%9C%CF%80%29%E7%9A%84%E5%9B%BE%E5%83%8F%E5%90%91%E5%B7%A6%E5%B9%B3%E7%A7%BB%CF%80%2F6%E4%B8%AA%E5%8D%95%E4%BD%8D%E5%90%8E%E5%BE%97%E5%88%B0%E5%81%B6%E5%87%BD%E6%95%B0g%28x%29%E7%9A%84%E5%9B%BE%E5%83%8F.%EF%BC%881%EF%BC%89%E6%B1%82%CF%86%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E6%B1%82%E5%87%BD%E6%95%B0h%28x%29%3Df%28x-%CF%80%2F12%29-g%28x%29%E7%9A%84%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4)
xRMN@LVCL(\S MLm\"4,bbb O;4^Pt1q1y2B># $* #oL/ Κ5ť*].gw[kup:Vz n7osі)*Aa5@\pD7 ^ wr)gfϧz
4ҡ "$T(+1 sx;fNn4DPGr YsNmĀI(M]oqAz5^F2%ڒ|k&({Lk}J؉0HNl[چg<,:
P݉wy'7ϥ? $
把函数f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.(1)求φ的值(2)求函数h(x)=f(x-π/12)-g(x)的单调增区间
把函数f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.
(1)求φ的值(2)求函数h(x)=f(x-π/12)-g(x)的单调增区间
把函数f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.(1)求φ的值(2)求函数h(x)=f(x-π/12)-g(x)的单调增区间
f(x)=2sin(2x+φ)(0<φ<π)的图像向左平移π/6个单位
g(x)=2sin(2(x+π/6)+φ)=2sin(2x+π/3+φ)=2cos(π/6-2x-φ)为偶函数;
所以g(x)=g(-x);
∴φ=π/6;
(2)h(x)=2sin(2x-π/6+π/6)-2cos2x
=2sin2x-2cos2x
=2√2(sin2x×√2/2-cos2x×√2/2)
=2√2sin(2x-π/4);
∴单调增区间为-π/2+2kπ≤2x-π/4≤π/2+2kπ;(K∈Z)
即-π/8+kπ≤x≤3π/8+kπ(k∈Z)
如果本题有什么不明白可以追问,
设函数f(x)=sin(2x+φ)(0
函数f(x)=sin(2x+φ)(0
已知函数f(x)=sin(2x+φ) (0
设函数f(x)=2sin(2x-3π/4)+1,把函数y=f(x) 的图象向左平移φ(0
函数f(x)=sin(2x+φ)((|φ|
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f x=SIN(2X+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
已知函数F(X)=SIN(2X+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+ φ)(-π
设函数f(x)=sin(2x+φ)(-π
设函数f(x)=sin(2x+ φ)(-π
设函数f(x)=sin(2x+φ)(-π
若函数f(x)=2sinωx(0