已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+10,则a=?,b=?
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已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+10,则a=?,b=?
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+10,则a=?,b=?
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+10,则a=?,b=?
(2x-3y+b)(3x+y+1)
=6x²-7xy-3y²+(2+3b)x+(b-3)y+b
=6x²-7xy-3y²+14x+y+a
所以2+3b=14
b-3=1
a=b
所以b=4,a=4
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