设f(x)在[0,1]上有连续导数,f(0)=0,0

设f(x)在[0,1]上有连续导数,f(0)=0,0 设f(x)在[0,1]上有连续导数,f(0)=0,0 设f(x)在[0,1]上有连续导数,且f(x)=f(0)=0.证明 设f(x)在[0,1]上有连续一阶导数,在（0,1）内二阶可导. 设f(x)在[0,1]上具有二阶连续导数,且|f''(x)| 设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(t)|+|f′(t)|)dt 设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(t)|+|f′(t)|)dt 设f(x)在[0,1]上有连续的一阶导数,且｜f'(x)｜≤M,f(0)=f(1)=0,证明： 设函数f(x)在[a,b]上有连续导数,且f(c)=0,a f(x)在［0,1］上有连续导数,f(0)=0,0 设函数f(x)在[a,b]上连续,在(a,b)内有二阶导数,且有f(a)=f(b)=0,f(c)>0(a 设f(x)在[0,1]上有连续导数,且f(0)=f(1)=0,证明|∫（0,1)f(x)dx|≤1/4max(0≤x≤1)|f'(x)| 设f(x)在[0,1]上有连续的二阶导数,f(0)=f(1)=0,f(x)不恒为零.证明：max|f(x)| 设f(x)在[0,1]上有二阶连续导数,且满足f(1)=f(0)及|f''(x)| 设函数f(x)在[0,b]上有连续的导数,且f(0)=0,记M=max|f'(x)|0 设函数f(x)在R上有连续导数,求lim1/4x^2S(f(t+x)-f(t-x))dt设函数f(x)在R上有连续导数,求lim1/4x^2S(x,x)(f(t+x)-f(t-x))dtS是积分号,-x是积分下限,x是积分上限,x趋向于０ 设f(x)在区间[a,b]上连续,且f(x)>0,证明 f(x)在[a,b]上的导数 乘 1/f(x)在[a,b]上的导数 >=(b-a)的平方 设函数f(x)在区间[0,1]上有连续导数,f(0)=1,且满足 ∫ ∫ Dt f'(x+y)dxdy= ∫ ∫ Dt f(t)dxdy,其中Dt={(x,y)|0