分别以锐角三角形的边AB,BC,CA为斜边向外作等腰RT三角形DAB,EBC,FAC求证:(1)AE=DF (2)AE垂直DF 只是我看不懂,不要照抄答案 延长BD至P,使DP=BD,连AP,CP AB/BP=BE/BC=根号下2除以2,角DBC=45+角ABC=角ABE,所以三角
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![分别以锐角三角形的边AB,BC,CA为斜边向外作等腰RT三角形DAB,EBC,FAC求证:(1)AE=DF (2)AE垂直DF 只是我看不懂,不要照抄答案 延长BD至P,使DP=BD,连AP,CP AB/BP=BE/BC=根号下2除以2,角DBC=45+角ABC=角ABE,所以三角](/uploads/image/z/5576101-61-1.jpg?t=%E5%88%86%E5%88%AB%E4%BB%A5%E9%94%90%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E8%BE%B9AB%2CBC%2CCA%E4%B8%BA%E6%96%9C%E8%BE%B9%E5%90%91%E5%A4%96%E4%BD%9C%E7%AD%89%E8%85%B0RT%E4%B8%89%E8%A7%92%E5%BD%A2DAB%2CEBC%2CFAC%E6%B1%82%E8%AF%81%3A%281%29AE%3DDF+%282%29AE%E5%9E%82%E7%9B%B4DF+%E5%8F%AA%E6%98%AF%E6%88%91%E7%9C%8B%E4%B8%8D%E6%87%82%2C%E4%B8%8D%E8%A6%81%E7%85%A7%E6%8A%84%E7%AD%94%E6%A1%88+%E5%BB%B6%E9%95%BFBD%E8%87%B3P%2C%E4%BD%BFDP%3DBD%2C%E8%BF%9EAP%2CCP+AB%2FBP%3DBE%2FBC%3D%E6%A0%B9%E5%8F%B7%E4%B8%8B2%E9%99%A4%E4%BB%A52%2C%E8%A7%92DBC%3D45%2B%E8%A7%92ABC%3D%E8%A7%92ABE%2C%E6%89%80%E4%BB%A5%E4%B8%89%E8%A7%92)
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