椭圆c:x²/a²+y²/b²=1(a>b>0)的离心率e=√3/2,短轴长为21)求椭圆c的方程2)椭圆c的右焦点F,判断是否存在在直线L过F与c相交于A、B两点,且以线段AB为直径的圆过原点O,若存在,则求出
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![椭圆c:x²/a²+y²/b²=1(a>b>0)的离心率e=√3/2,短轴长为21)求椭圆c的方程2)椭圆c的右焦点F,判断是否存在在直线L过F与c相交于A、B两点,且以线段AB为直径的圆过原点O,若存在,则求出](/uploads/image/z/5580259-43-9.jpg?t=%E6%A4%AD%E5%9C%86c%EF%BC%9Ax%26%23178%3B%2Fa%26%23178%3B%2By%26%23178%3B%2Fb%26%23178%3B%3D1%EF%BC%88a%3Eb%3E0%29%E7%9A%84%E7%A6%BB%E5%BF%83%E7%8E%87e%3D%E2%88%9A3%2F2%2C%E7%9F%AD%E8%BD%B4%E9%95%BF%E4%B8%BA21%EF%BC%89%E6%B1%82%E6%A4%AD%E5%9C%86c%E7%9A%84%E6%96%B9%E7%A8%8B2%EF%BC%89%E6%A4%AD%E5%9C%86c%E7%9A%84%E5%8F%B3%E7%84%A6%E7%82%B9F%2C%E5%88%A4%E6%96%AD%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8%E5%9C%A8%E7%9B%B4%E7%BA%BFL%E8%BF%87F%E4%B8%8Ec%E7%9B%B8%E4%BA%A4%E4%BA%8EA%E3%80%81B%E4%B8%A4%E7%82%B9%2C%E4%B8%94%E4%BB%A5%E7%BA%BF%E6%AE%B5AB%E4%B8%BA%E7%9B%B4%E5%BE%84%E7%9A%84%E5%9C%86%E8%BF%87%E5%8E%9F%E7%82%B9O%2C%E8%8B%A5%E5%AD%98%E5%9C%A8%2C%E5%88%99%E6%B1%82%E5%87%BA)
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