f(x)=sin²(x+π/4)-sin²(x-π/4)求出周期判断是奇函数还是偶函数
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f(x)=sin²(x+π/4)-sin²(x-π/4)求出周期判断是奇函数还是偶函数
f(x)=sin²(x+π/4)-sin²(x-π/4)求出周期判断是奇函数还是偶函数
f(x)=sin²(x+π/4)-sin²(x-π/4)求出周期判断是奇函数还是偶函数
前面那个是a 后面那个是b
少侠又是你.
sin平方a-sin平方b=(sina+sinb)(sina-sinb)
=sin((a+b)/2) cos((a-b)/2) cos((a+b)/2) sin((a-b)/2)
=1/4sin(a+b)sin(a-b)=1/4 sin2x sinπ/2
sin2x奇偶性跟周期会了吧.