如果(x²+px+8)(x²-3x+q)的乘积中不含x²与x³项.求p,q的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/29 21:08:32
![如果(x²+px+8)(x²-3x+q)的乘积中不含x²与x³项.求p,q的值](/uploads/image/z/5623247-47-7.jpg?t=%E5%A6%82%E6%9E%9C%28x%26%23178%3B%2Bpx%2B8%29%28x%26%23178%3B%EF%BC%8D3x%2Bq%29%E7%9A%84%E4%B9%98%E7%A7%AF%E4%B8%AD%E4%B8%8D%E5%90%ABx%26%23178%3B%E4%B8%8Ex%26%23179%3B%E9%A1%B9.%E6%B1%82p%2Cq%E7%9A%84%E5%80%BC)
x){ټ9jʆ0=څg<9Ov}POvY/{@i"}_`gC[cVc&Xvb8[/5.жPk g#Vhkh_\g2 I
如果(x²+px+8)(x²-3x+q)的乘积中不含x²与x³项.求p,q的值
如果(x²+px+8)(x²-3x+q)的乘积中不含x²与x³项.求p,q的值
如果(x²+px+8)(x²-3x+q)的乘积中不含x²与x³项.求p,q的值
乘积中不含x³项,则
-3+p=0
解得
p=3
乘积中不含x²项,则
q-3p+8=0
q-9+8=0
解得
q=1