已知(x²+px+q)(x²-3x+q)的乘积中不含x²和x³项,求p,q的值.
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已知(x²+px+q)(x²-3x+q)的乘积中不含x²和x³项,求p,q的值.
已知(x²+px+q)(x²-3x+q)的乘积中不含x²和x³项,求p,q的值.
已知(x²+px+q)(x²-3x+q)的乘积中不含x²和x³项,求p,q的值.
(x^2+px+q)(x^2-3x+q)=x^4-3*x^3+qx^2+p*x^3-3px^2+pqx+qx^2-3qx+q^2
=x^4+(p-3)x^3+(q-3p+q)x^2+(pq-3q)x+q^2
其中没有x^3和x^2
∴ p-3=0
2q-3p=0
所以 p=3
q=9/2