证明:sin²α+sin²β-sin²αsin²β+cos²αcos²β=1
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证明:sin²α+sin²β-sin²αsin²β+cos²αcos²β=1
证明:sin²α+sin²β-sin²αsin²β+cos²αcos²β=1
证明:sin²α+sin²β-sin²αsin²β+cos²αcos²β=1
sin²α+sin²β-sin²αsin²β+cos²αcos²β
=sin²α(1-sin²β)+sin²β+cos²αcos²β
=sin²αcos²β+sin²β+cos²αcos²β
=(sin²α+cos²α)cos²β+sin²β
=cos²β+sin²β
=1