(-2y-3x)(3x-2y)怎么算啊?一定要正确!
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(-2y-3x)(3x-2y)怎么算啊?一定要正确!
(-2y-3x)(3x-2y)怎么算啊?
一定要正确!
(-2y-3x)(3x-2y)怎么算啊?一定要正确!
原式=-(3x+2y)(3x-2y)
=-(9x^2-4y^2)
=4y²-9x²
(-2y-3x)(3x-2y) = -6xy + 4y^2-9x^2+6xy=4y^2-9x^2
或者直接用平方差公式可得 原式 = (-2y)^2 - (3x)^2
= 4y^2-9x^2
(-2y-3x)(3x-2y)= -(3x+2y)(3x-2y)
= -(9x^-4y^)=4y^-9x^
把前一个括号中的负号提到后一括号中,得(2x+3y)(2x-3y)=4x*x-9y*y
(-2y-3x)(3x-2y)=-6xy+4y平方-9X平方+6XY=4Y平方-9X平方
原式=-(3x+2y)(3x-2y)
=-(9x^2-4y^2)
=4y^2-9x^2
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