求定积分∫[1,2]dx/x.(答案是ln2),不要用公式,用定义法求,①记号∫[1,是指∫[1,2] (1/x)dx吗?②如果是,那我做到这一步:∫[1,2] (1/x)dx=lim(n→∞)∑xi△x=∑[1/1+(1/n)]△x(i=1,2,3,...,n)又∵∑[1/1+
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![求定积分∫[1,2]dx/x.(答案是ln2),不要用公式,用定义法求,①记号∫[1,是指∫[1,2] (1/x)dx吗?②如果是,那我做到这一步:∫[1,2] (1/x)dx=lim(n→∞)∑xi△x=∑[1/1+(1/n)]△x(i=1,2,3,...,n)又∵∑[1/1+](/uploads/image/z/5688135-63-5.jpg?t=%E6%B1%82%E5%AE%9A%E7%A7%AF%E5%88%86%E2%88%AB%5B1%2C2%5Ddx%2Fx.%28%E7%AD%94%E6%A1%88%E6%98%AFln2%29%2C%E4%B8%8D%E8%A6%81%E7%94%A8%E5%85%AC%E5%BC%8F%2C%E7%94%A8%E5%AE%9A%E4%B9%89%E6%B3%95%E6%B1%82%2C%E2%91%A0%E8%AE%B0%E5%8F%B7%E2%88%AB%5B1%2C%E6%98%AF%E6%8C%87%E2%88%AB%5B1%2C2%5D+%EF%BC%881%2Fx%EF%BC%89dx%E5%90%97%3F%E2%91%A1%E5%A6%82%E6%9E%9C%E6%98%AF%2C%E9%82%A3%E6%88%91%E5%81%9A%E5%88%B0%E8%BF%99%E4%B8%80%E6%AD%A5%EF%BC%9A%E2%88%AB%5B1%2C2%5D+%EF%BC%881%2Fx%EF%BC%89dx%3Dlim%28n%E2%86%92%E2%88%9E%29%E2%88%91xi%E2%96%B3x%3D%E2%88%91%5B1%2F1%2B%EF%BC%881%2Fn%EF%BC%89%5D%E2%96%B3x%28i%3D1%2C2%2C3%2C...%2Cn%29%E5%8F%88%E2%88%B5%E2%88%91%5B1%2F1%2B)
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