已知|M+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式已知|m+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式
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![已知|M+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式已知|m+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式](/uploads/image/z/573830-62-0.jpg?t=%E5%B7%B2%E7%9F%A5%7CM%2B4%7C%2Bn%5E2-2n%2B1%3D0+%E6%8A%8A%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%88x%26%23178%3B%2B4y%26%23178%3B%EF%BC%89-%EF%BC%88mxy%2Bn%EF%BC%89%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%E5%B7%B2%E7%9F%A5%7Cm%2B4%7C%2Bn%5E2-2n%2B1%3D0+%E6%8A%8A%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%88x%26%23178%3B%2B4y%26%23178%3B%EF%BC%89-%EF%BC%88mxy%2Bn%EF%BC%89%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F)
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已知|M+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式已知|m+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式
已知|M+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式
已知|m+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式
已知|M+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式已知|m+4|+n^2-2n+1=0 把多项式(x²+4y²)-(mxy+n)分解因式
|M+4|+n^2-2n+1=0
|M+4|>=0,n^2-2n+1=(n-1)²>=0
M+4=n-1=0
m=-4,n=1
(x²+4y²)-(mxy+n)
=x²+4y²+4xy-1
=(x+2y)²-1
=(x+2y+1)(x+2y-1)
|m+4|+n^2-2n+1=0
|m+4|+(n-1)²=0
m+4=0,m=-4
n-1=0,n=1
(x²+4y²)-(mxy+n)
=(x²+4y²)-(-4xy+1)
=x²+4y²+4xy-1
=(x+2y)²-1
=(x+2y+1)(x+2y-1)
|m+4|+n^2-2n+1=|m+4|+(n-1)^2=0 即m=-4, n=1
多项式即为(x²+4y²)-(-4xy+1)=x²+4y²+4xy-1=(x+2y)^2-1
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