如果xyz+xy+yz+zx+x+y+z=1975,求自然数x,y,z过程~

如果xyz+xy+yz+zx+x+y+z=1975,求自然数x,y,z过程~ 分解因式：xyz-yz-zx-xy+x+y+z-1 分式题:xy=x+y,yz=2(y+z),zx=3(z+x),求xyz/(xy+yz+xz)xy=x+y,yz=2(y+z),zx=3(z+x),求xyz/(xy+yz+xz) 求证不等式 xyz[yz(y+z)+zx(z+x)+xy(x+y)]>=2(xy+yz+xz)^2 XYZ满足XY/X+Y=-2,YZ/Y+Z=3/4,ZX/Z+X=-4/3,求XYZ/XY+YZ+ZX的值 一道因式分解题,急xyz+xy+yz+zx+x+y+z+1 已知x,y,z>0 求证:xy(x+y)+yz(y+z)+zx(z+x)>=6xyz x+y分之xy=5,y+z分之yz=2分之7,z+x分之zx=4,则xy+yz+zx分之xyz=? 若x+y+z=6,xy+yz+zx=11,xyz=6,则x/yz+y/zx+z/xy= 若x+y+z=6,xy+yz+zx=11,xyz=6,则x/yz+y/zx+z/xy= xy 2yz 3zx 4xyz________ = ________ = _______ = ___________ (xyz不等于0)x+y+xy y+z+yz z+x+zx xy+yz+zx最好有解题思路 算出 X Y Z 分别等于几 若xyz=1,求 x/(xy+x+1) +y/(yz+y+z) +z/(zx+z+1)越快越好~. 已知xyz=1求(x/xy+x+1)+(y/yz+y+1)+(z/zx+z+1)的值 已知xyz均为正数,求证:x/yz+y/zx+z/xy≥1/x+1/y+1/z. 若x+y+z=6,xy+yz+zx=11,x^3+y^3+z^3-3xyz 设XYZ=1,求X/(XY+X+1)+Y/(YZ+y+1）+Z/(ZX+Z+1)的值 xy(x-y)+yz(y-z)+zx(z-x)因式分解 (x+y-xy)/(x+y+2xy)=(y+z-2yz)/(y+z+3yz)=(z+x-3zx)/(z+x+4zx),且2/x=3/y=1/z,则xyz=?