如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A

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如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A
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如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A
如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A

如图,BP,CP分别平分∠ABC和∠ACB,求证:∠BPC=90°+1/2∠A
∠BPC + ∠PBC +∠PCB = 180
∠BPC+1/2∠ABC+1/2∠ACB=180 (1)
∠A +∠ABC+∠ACB=180
1/2∠A+1/2∠ABC+1/2∠ACB=90 (2)
(1) — (2) 得
:∠BPC=90°+1/2∠A