2852=1.2X(1+(X-1000)/2000)^1.6

来源：学生作业帮助网编辑：作业帮时间：2024/08/01 02:32:38

x��J�0�_e݆͟&i"K/��4I��b�& ��^<Q�ƺ�|�M��_~|�_>�ts�%�qk�e��4� �M��s٬�v��H��?��wo��r��d��̿�+)��1>z�-ή^��~�U�5�Tq��zyZyS��|�&-h�v6��4t��/��_0�ڬ��e6��epZΟꙄ�+�$5��Q>;�V��7�4��xcG��z-�ղeY2@hGq��^j+?6{��m��(6~�G g�A��B��mi ��1�,0s��+pFH�B�|�)��K\H�S�)6�`ߧ��I��Bh��>] 6��!הg�`C$ �Ό.�s�4��O��

2852=1.2*X*(1+(X-1000)/2000)^1.6
2852=1.2*X*(1+(X-1000)/2000)^1.6

2852=1.2*X*(1+(X-1000)/2000)^1.6
答：
1.2x[1+(x-1000)/2000]^1.6=2852
转化为：
[1+(x-1000)/2000]^1.6=2852/(1.2x)
函数f(x)=[1+(x-1000)/2000]^1.6=(1/2+x/2000)^1.6=(0.5+t)^1.6
函数g(x)=2852/(1.2x)=(2852/2400)/(x/2000)=(2852/2400)/t的图像见下图：
t=0.79=x/2000
x=1580

（X+X)+(X-X)+(X*X)+(X/X)=100 1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)= 解方程：2x+4x+6x...+100x=1-(x+3x+5x+...+99x) 1X+2X+3X…+98X+99X+100X=50500X X等于多少? 1x+2x+3x+4x+5x+6x+7x…+99x=100 设函数f(x)=(x-1)(x-2)...(x-100)(x>100),求F'(X) f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100) X(X-1)=X 已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值 f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1) 2852=1.2*X*(1+(X-1000)/2000)^1.6 x>=1,x X+X+X+X+X+X+100X=1690 问：X等于多少已知x=100,求x(x+1)分之1+(x+1)(x+2)分之1+(x+2)(x+3)分之1+.+(x+99)(x+100)分之1 x/x-2+x-9/x-7=x+1/x-1+x-8/x-6, x/x-2+x-9/x-7=x+1/x-1+x-8/x-6, 【1】f[x]=x[x+1][x+2].[x+100][2]f[x]=a0 x^n+a1 x^[n-1]+.a[n-1]x+ an 1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=?