x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 00:22:28
![x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010](/uploads/image/z/580539-3-9.jpg?t=x-2%2F%28x%5E2-9%29%281%2B%282x-7%2Fx%5E2-4x%2B4%29%C3%B7%28x%2B1%29%2F%28x%2B3%29%E5%85%B6%E4%B8%ADx%3D2010)
x)5ר3ҵ005qM*M4oר6*6|ںɎF6IEj/^[
f$iyxFH@"px:X>H\)pXB{'Cl6@{Aj@0e@~qAb fso
x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010
x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010
x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010
=(x-2)/(x+3)(x-3)× (x²+2x-3)/(x-2)² ×(x+3)/(x+1)
=(x-2)/(x+3)(x-3)×(x-3)(x+1)/(x-2)²×(x+3)/(x+1)
=1/(x-2)
当x=2010时
原式=1/(2010-2)
=1/2008