若|x-3y+5|+(3x+y-5 2 ) +√x+y-3z=0,求√x+y+z的值
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若|x-3y+5|+(3x+y-5 2 ) +√x+y-3z=0,求√x+y+z的值
若|x-3y+5|+(3x+y-5 2 ) +√x+y-3z=0,求√x+y+z的值
若|x-3y+5|+(3x+y-5 2 ) +√x+y-3z=0,求√x+y+z的值
|x-3y+5|+(3x+y-5 )² +√x+y-3z=0
∴﹛x-3y+5=0
3x+y-5=0
x+y-3z=0
解得x=1,y=2,z=1
∴√﹙x+y+z)=√(1+2+1)=√4=2
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