作业帮用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
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![用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为](/uploads/image/z/585422-62-2.jpg?t=%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A3%E6%96%B9%E7%A8%8B%5B6%28x%2B1%29%2F%28x%5E2%29%2Bx%5E2%2F%28x%2B1%29%5D%3D7%2C%E8%8B%A5%E8%AE%BEx%5E2%2Fx%2B1%3Dy%2C%E5%88%99%E5%8E%9F%E6%96%B9%E7%A8%8B%E5%8F%AF%E5%8C%96%E4%B8%BA)
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用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
用换元法解方程[6(x+1)/(x^2)+x^2/(x+1)]=7,若设x^2/x+1=y,则原方程可化为
设x^2/x+1=y,则原方程可化为
6/y+y=7
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