用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=_______,则原方程变形为______________
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![用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=_______,则原方程变形为______________](/uploads/image/z/585499-67-9.jpg?t=%E7%94%A8%E6%8D%A2%E5%85%83%E6%B3%95%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A%5B8%28x%5E2%2B2x%29%2Fx%5E2-1%5D%2B%5B3%28x%5E2-1%EF%BC%89%2Fx%5E2%2B2x%5D%3D11%2C%E5%8F%AF%E8%AE%BEy%3D_______%2C%E5%88%99%E5%8E%9F%E6%96%B9%E7%A8%8B%E5%8F%98%E5%BD%A2%E4%B8%BA______________)
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用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=_______,则原方程变形为______________
用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=_______,则原方程变形为______________
用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=_______,则原方程变形为______________
用换元法解方程:[8(x^2+2x)/x^2-1]+[3(x^2-1)/x^2+2x]=11,可设y=(x²+2x)/(x²-1),则原方程变形为8y+3÷y=11
(1)y=(x^2+2x)/x^2-1
(2)8y^2-11y[(x^2-1)/x^2+2x]+[3(x^2-1)/x^2+2x]=0
此时,令a={(x^2-1)/(x^2+2x)}......y1=(-11+5a)/32
y2=(-11-5a)/32