解方程:(x+1)(x-1)分之6减去x-1分之3=1

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解方程:(x+1)(x-1)分之6减去x-1分之3=1
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解方程:(x+1)(x-1)分之6减去x-1分之3=1
解方程:(x+1)(x-1)分之6减去x-1分之3=1

解方程:(x+1)(x-1)分之6减去x-1分之3=1
6-3(x+1)=x^2-1
x^2+3x-4=0
(x+4)(x-1)=0
x=-4或x=1

6/(x+1)(x-1)-3/(x-1)=1
6/(x+1)(x-1)-3(x+1)/(x-1)(x+1)=1
6-3(x+1)=(x-1)(x+1)
3-3x=x^2-1
x^2+3x-4=0
(x-1)(x+4)=0
因为x-1为分母,所以不能为零,所以x=-4

6/(x+1)(x-1)-3/(x-1)=1
6/(x+1)(x-1)-3(x+1)/(x+1)(x-1)=1
(6-3(x+1))/(x+1)(x-1)-1
即(3-3x)/(x+1)(x-1)=1
-3(x-1)/(x+1)(x-1)=1
-3/(x+1)=1
即-3=x+1
所以x=-4

6/(x+1)(x-1)-3(x+1)/(x+1)(x-1)=1
6-3x+3/(x+1)(x-1)=1
6-3x+3=x^2-1
x^2+3x-4=0
x=-4或x=1(,因为分么不能为零,舍去)