(1)a²-x²y²=?(2)2(y-x)²+3(x-y)=?(3)4-12(x-y)+9(x-y)=
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(1)a²-x²y²=?(2)2(y-x)²+3(x-y)=?(3)4-12(x-y)+9(x-y)=
(1)a²-x²y²=?(2)2(y-x)²+3(x-y)=?(3)4-12(x-y)+9(x-y)=
(1)a²-x²y²=?(2)2(y-x)²+3(x-y)=?(3)4-12(x-y)+9(x-y)=
1、a²-x²y²=(a+xy)(a-xy)
2、2(y-x)²+3(x-y)
=2(x-y)²+3(x-y)
=(x-y)[2(x-y)+3]
=(x-y)(2x-2y+3)
3、4-12(x-y)+9(x-y)²
=[2-3(x-y)]²
=(2-3x+3y)²
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分解因式?
(1)a²-x²y²=(a+xy)(a-xy)
(2)2(y-x)²+3(x-y)
= 2(x-y)²+3(x-y)
=(x-y)[2(x-y)+3]
=(x-y)(2x-2y+3)
(3)4-12(x-y)+9(x-y)²
=[2-3(x-y)]²
=(2-3x+3y)²